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graph the line with the slope -2/5 and y-intercept (0,2)

Sagot :

a386
Use slope intercept form:
[tex]y=mx+b[/tex]

m is the slope.
b is the y-intercept.

Your y-intercept is only the y value in your point (0,2), which is 2.  We don't need the x value because it is understood that it will be 0 because the x-value at the y-axis is always 0 (think of the typical graph).

Just plug in (-2/5) for m and 2 for b

[tex]y=mx+b\\ y=-\frac{2}{5}x+2[/tex]

To graph, place a point at the y-cept: (0,2) and, using the rise over run method, place a point 2 down and 5 to the right of the point. Then connect the points. I've included a picture.
View image a386
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