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How to solve 1/2(1/3w+4)+6=10 and -5(h+4)=12

Sagot :

luana
[tex]\frac{1}{2}(\frac{1}{3}w+4)+6=10\\\\ \frac{1}{6}w+\frac{4}{2}+6=10\\\\ \frac{1}{6}w+2+6=10\\\\ \frac{1}{6}w+8=10\ \ \ |Subtract\ 8\\\\ \frac{1}{6}w=2\ \ \ |Multiply\ by\ 6\\\\ \boxed{w=12}\\\\\\ -5(h+4)=12\\\\ -5h-20=12\ \ \ |Add\ 20\\\\ -5h=32\ \ |Divide\ by\ -5\\\\ h=-\frac{32}{5}=-6\frac{2}{5}\\\\ \boxed{h=-6\frac{2}{5}}[/tex]
1/2(1/3w+4)+6=10            -5(h+4)=12
5/6w+2+6=10                    -5h-20=12
5/6w+8=10                            +20    +20
       -8    -8                        -5h=32
5/6w=2                              -5h/5=32/5
·6      ·6                              h=32/5
5w=12
5w/5=12/5
w=12/5