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Sagot :
[tex]f(x)=2x+2 \\\\ f(x)-1= (2*4+2)-1 \\\\ =8+2-1= \\\\ =10-1= \\\\=\boxed{9}[/tex]
[tex]f(x)=2x+2\\\\
f^{-1}(x):\\
y=2x+2\\
y-2=2x\ \ \ |Divide\ by\ 2\\
\frac{y-2}{2}=x\\\\
f^{-1}(x)=\frac{x-2}{2}\\
f^{-1}(4)=\frac{4-2}{2}=1\\\\
Solution\ is\ f^{-1}(4)=1[/tex]
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