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Sagot :
[tex]f(x)=5x+12\\\\
f^{-1}(x):\\
y=5x+12\ \ \ |Subtract\ 12\\
y-12=5x\ \ \ |Divide\ by\ 5\\
\frac{y-12}{5}=x\\\\
f{-1}(x)=\frac{x-12}{5}[/tex]
Answer:
f^-1(x) = x/5 - 12/5
Step-by-step explanation:
f(x) = 5x + 12
y = 5x + 12
x = 5y + 12
5y = x - 12
y = x/5 - 12/5
f^-1(x) = x/5 - 12/5
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