pietschaaron72
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A tennis ball is thrown vertically upward with an initial velocity of 8.0 m/s. What will be its velocity when it returns to its starting point? How long will it take to reach its starting point?

Sagot :

AL2006
-- The velocity of the ball when it plunks back into the thrower's hand
will be the same 8.0 m/s but directed downwards this time.

-- Gravity robs 9.8 m/s from upward velocity each second.  The ball can only
stand this for  (8.0 / 9.8) = 0.816 second (rounded) before it stops rising and
begins to fall.

The round trip, from the thrower's hand, to the peak of the arc, and back to his
hand, takes (0.816 x 2) = 1.633 second. (rounded)    
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.