voytek
Answered

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Solve for x: x^2+4x-5=16x

Sagot :

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Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
x²-12x-5=0
now we have a quadratic. we can solve it by using the quadratic formula
x=-b plus or minus the square root of b²-4ac all divided by 2a
where a=1, b=-12 and c=-5
plug these numbers into the formula
x=12 plus or minus the square root of 144-4x1x-5 all divided by 2
x=12 plus or minus the square root of 164 all divided by 2
or in decimal form x = {12.403124237, -0.403124237}
konrad509
[tex]x^2+4x-5=16x\\ x^2-12x-5=0\\ x^2-12x+36-41=0\\ (x-6)^2=41\\ x-6=\sqrt{41} \vee x-6=-\sqrt{41}\\ x=6+\sqrt{41} \vee x=6-\sqrt{41}[/tex]
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