voytek
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Solve for x: x^2+4x-5=16x

Sagot :

logo88
Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
x²-12x-5=0
now we have a quadratic. we can solve it by using the quadratic formula
x=-b plus or minus the square root of b²-4ac all divided by 2a
where a=1, b=-12 and c=-5
plug these numbers into the formula
x=12 plus or minus the square root of 144-4x1x-5 all divided by 2
x=12 plus or minus the square root of 164 all divided by 2
or in decimal form x = {12.403124237, -0.403124237}
konrad509
[tex]x^2+4x-5=16x\\ x^2-12x-5=0\\ x^2-12x+36-41=0\\ (x-6)^2=41\\ x-6=\sqrt{41} \vee x-6=-\sqrt{41}\\ x=6+\sqrt{41} \vee x=6-\sqrt{41}[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.