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2 dice are rolled. What is the probability that the sum of the numbers rolled is a number greater than or eaqual to 5

Sagot :

crisforp
2 + 3 = 5 > = 5;
2 + 4 = 6 > =5;
2 + 5 = 7 >= 5;
2 + 6 = 8 >= 5;
3+2 = 5 >= 5;
3 + 3 = 6  >= 5;
3 + 4 = 7  >= 5;
3 + 5 = 8  >= 5;
3 + 6 = 9  >= 5;
4+1 = 5  >= 5;
4+2 = 6  >= 5;
4+3 = 7  >= 5;
4+4 = 8  >= 5;
4+5 = 9  >= 5;
4+6 = 10  >= 5;
5+1 = 6  >= 5;
5+2 = 7  >= 5;
..............

6 + 6 = 12  >= 5;


Number of ways it can happen = 27;

Total number of outcomes = 6*6 = 36;



Probability of an event happening = Number of ways it can happen / Total number of outcomes => Probability = 27/36 = 0.75;
ashlynn11051994

Answer:1/3

Step-by-step explanation:

So first we need our denominator. Which we can get by adding all the possibilities so there are 6 sides on each dice. 6+6=12 So there is our bottom half. There are two 5's and two 6's so that's four.  So we have 4 as a numerator . Let's put them together now 4/12. Now we can reduce this to 2/6. We can reduce it again to 1/3 and that would be your answer.

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