Answered

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how do you solve for sinxcos2x+cosxsin2x=0 ?

Sagot :

priyambaksi
LHS is nothing but (using sin (a+b) = sin a cos b + cos a sin b)

sin (x+2x) = sin 3x = 0

so 3x = npi
or
x = npi/3

The answer is x = n p i divided by 3
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