At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

the teacher separated her class of twenty-eight student into two group. one group has 4 more than twice as many students as the other group. how many students are in each group?

Sagot :

W0lf93
There are 20 students in one group and 8 students in the other. To represent this as an equation, x + y = 28, where y = 2x + 4. Therefore, x + 2x + 4 = 28. 3x + 4 = 28. 3x = 24. x = 24/3. x = 8. Put the x value into the y equation and it gives you 20.

For this case, the first thing we must do is define variables:

x: students of group 1

y: students of group 2

We now write the system of equations that models the problem:

[tex] x + y = 28

y = 2x + 4
[/tex]

Solving the system by substitution we have:

[tex] x + (2x + 4) = 28

3x + 4 = 28

3x = 28-4
[/tex]

[tex] 3x = 24
[/tex]

[tex] x = \frac{24}{3}

x = 8
[/tex]

Then, the value of y is given by:

[tex] y = 2 (8) +4

y = 16 + 4

y = 20
[/tex]

Answer:

8 students of group 1

20 students of group 2