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Sagot :
$24
$8 and $6
8x1 = 8 ; 8x2 = 16 ; 8x3 = 24
6x1 = 6 ; 6x2 = 12 ; 6x3 = 18 ; 6x4 = 24
$24 dollars
$8 and $6
8x1 = 8 ; 8x2 = 16 ; 8x3 = 24
6x1 = 6 ; 6x2 = 12 ; 6x3 = 18 ; 6x4 = 24
$24 dollars
Answer:
The least amount of money they could have spent is $24
Explanation:
To get the least amount of money they could have spent, we will need to get the lowest common multiple of both numbers (6 and 8).
This means that we need to find that least number that is found in both multiplication tables
Multiples of 6:
6 * 1 = 6
6 * 2 = 12
6 * 3 = 18
6 * 4 = 24
Multiples of 8:
8 * 1 = 8
8 * 2 = 16
8 * 3 = 24
Noticing the two multiples, we can note that the lowest common multiple is 24.
This means that the lowest amount they could have spent is 24
Hope this helps :)
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