emilybb195
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring

Sagot :

rabinshrestha41
so what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)
    
here ,
energy required = 10.0°C                Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C    Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= [tex] \frac{10}{3.1*17.9} [/tex]
 
                                   = [tex]0.1802126509[/tex]
      
                                   = 0.1802 cal./g°C            i rounded the answer to the                                                                                      fourth decimal point




Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.