emilybb195
Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring

Sagot :

rabinshrestha41
so what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)
    
here ,
energy required = 10.0°C                Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C    Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= [tex] \frac{10}{3.1*17.9} [/tex]
 
                                   = [tex]0.1802126509[/tex]
      
                                   = 0.1802 cal./g°C            i rounded the answer to the                                                                                      fourth decimal point




Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.