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Sagot :
32 2/5 = 162/5
162/9 = 18
18 x 5 = 90
90/10 = 9
9 x 3 = 27.
That makes Ramiro 27/5 feet tall or you can also say he's 5 2/5 feet tall.
162/9 = 18
18 x 5 = 90
90/10 = 9
9 x 3 = 27.
That makes Ramiro 27/5 feet tall or you can also say he's 5 2/5 feet tall.
Let
x---------> Ramiro's height
y--------> height of the flagpole
z-------> height of the tree
we know that
[tex] z=32\frac{2}{5} \\\\ z=(32*5+2)/5\\\\ z=\frac{162}{5} ft [/tex]
1) Find the height of the flagpole
[tex] y=\frac{5}{9} *\frac{162}{5} \\\\ y=\frac{162}{9} \\\\ y=18 ft [/tex]
2) Find the height of Ramiro
[tex] x=\frac{3}{10} *18\\ \\ x=\frac{54}{10} \\ \\ x=5.4 ft\\ \\ x=5\frac{2}{5} ft [/tex]
therefore
the answer is
The height of Ramiro is [tex] 5\frac{2}{5} ft [/tex]
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