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suma a trei numere este 3932/Primul numar este cu 1330mai mare decat al doilea si cu 1740mai mare decat al treilea determinati cele trei numere vreau rezolvare de clasa a 5 a

Sagot :

tsorin99
a+b+c= 3932

a=b+1330
a=c+1740 ⇒c=a-1740⇒c=(b+1330)-1740

Obt. 

b+1330 +b+(b+1330)-1740=3932 ⇒3b+2660-1740=3932⇒3b+920=3932⇒3b=3932-920⇒3b=3012⇒b=3012/3⇒[tex]\boxed{b=1004}[/tex]


a=b+1330⇒a=1004+1330⇒[tex]\boxed{a=2334}[/tex]

c=a-1740⇒c=23334-1740⇒[tex]\boxed{c=594}[/tex]
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