At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Food A has fewer calories per serving.
I found this by taking the first food (A) and dividing 150 by 3. This gave me 50, which I added onto 150 to give me my 4/4 of a serving (200 calories).
With food B, I did the same process. I took 250/2 and added that to the original amount to get the final third of the serving, which resulted in food B being 375 calories.
I found this by taking the first food (A) and dividing 150 by 3. This gave me 50, which I added onto 150 to give me my 4/4 of a serving (200 calories).
With food B, I did the same process. I took 250/2 and added that to the original amount to get the final third of the serving, which resulted in food B being 375 calories.
I have the same problem on my homework :P
I finished mine in class...
I got food A has less cal because you divide 150 by 3 then to get 1/3 if 150 (which is 50) and add 50 to 150 to find the total calories which is 200.
For food B you do the same thing. You divide by three to get 1/3 and add that to 250. To get 375 cal which is more than food A :)
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.