At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
You don't say how many numbers you want to do that with.
If you want just two numbers, then they're +7.3107 and -12.3107 .
(Those are rounded, not exact.)
I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
If you want just two numbers, then they're +7.3107 and -12.3107 .
(Those are rounded, not exact.)
I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
let
x-------> the first number
y-------> the second number
we know that
[tex]x+y=-5 \\ x=-5-y[/tex] equation 1
[tex]x*y=-90[/tex] equation 2
substitute the equation 1 in equation 2
[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311
x-------> the first number
y-------> the second number
we know that
[tex]x+y=-5 \\ x=-5-y[/tex] equation 1
[tex]x*y=-90[/tex] equation 2
substitute the equation 1 in equation 2
[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.