Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
You don't say how many numbers you want to do that with.
If you want just two numbers, then they're +7.3107 and -12.3107 .
(Those are rounded, not exact.)
I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
If you want just two numbers, then they're +7.3107 and -12.3107 .
(Those are rounded, not exact.)
I took a quick look among the factors of 90, looking for sets of 3 numbers
that would do it, and I couldn't find any.
let
x-------> the first number
y-------> the second number
we know that
[tex]x+y=-5 \\ x=-5-y[/tex] equation 1
[tex]x*y=-90[/tex] equation 2
substitute the equation 1 in equation 2
[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311
x-------> the first number
y-------> the second number
we know that
[tex]x+y=-5 \\ x=-5-y[/tex] equation 1
[tex]x*y=-90[/tex] equation 2
substitute the equation 1 in equation 2
[tex][-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0[/tex]
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are
-12.311
7.311

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.