Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Well take 2.3 kg and divide it by .84 to get 2.738 kg then divide the percent of S in the compounds by adding the atomic masses and dividing the atomic mass of S by the atomic mass of the molecule to get 13.40% S by mass
Then you know that Pb is 86.6% by mass so divide 2.738 by .866 to get your answer. Your answer is 3.162 kg of rock is needed
Then you know that Pb is 86.6% by mass so divide 2.738 by .866 to get your answer. Your answer is 3.162 kg of rock is needed
Answer: 3.162 kg
Explanation:
1) Mass percent = (mass of a part / total mass) × 100
2) 84% PbS by mass.
Percent PbS = ( mass of pure PbS / mass of the rock) × 100 = 84%
⇒ mass of the rock = mass of pure PbS × 100 / 84 =
⇒ mass of the rock = mass of pure PbS / 0.84 ← this is fhe formula that you will uise at the end.
2) Determine the mass of pure PbS that contains 2.3 kg of Pb
i) Unit formula: PbS
ii) molar mass of PbS: 207.2 g/mol + 32.065 g/mol = 239.265 g/mol
iii) proportion:
207.2 g of Pb / 239.265 g of PbS = 2,300 g of Pb / x
⇒ x = 2,300 × 239.265 g of PbS / 207.2 = 2,655.93 g of PbS = 2.656 Kg of PbS
4) Use the formula to determine how many kilograms of the rock contain 2.565 kg of pure PbS
mass of the rock = mass of pure PbS / 0.84 = 2.565 / 0.84 = 3.162 kg
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.