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Sagot :
option I
(3x+4)cm =(2x+10)cm
3x-2x=6
x=6
Option II
(3x+4)= (x+12)
3x-x=12-4
2x=8
x=4
Option III
(2x+10)= (x+12)
2x-x=12-10
x=2
(3x+4)cm =(2x+10)cm
3x-2x=6
x=6
Option II
(3x+4)= (x+12)
3x-x=12-4
2x=8
x=4
Option III
(2x+10)= (x+12)
2x-x=12-10
x=2
Isosceles triangles, are triangles where two of the lengths are the same so we can say that:
1. (3x+4)=(2x+10)
2. (3x+4)=(x+12)
3. (2x+10)=(x+12)
One of these must be true. Solve as simultaneous equations.
1. x=6
2. x=4
3. x=2
1. (3x+4)=(2x+10)
2. (3x+4)=(x+12)
3. (2x+10)=(x+12)
One of these must be true. Solve as simultaneous equations.
1. x=6
2. x=4
3. x=2
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