Answered

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Calculate the magnitude of the horizontal vector that is 100 units long and is oriented at 45 degrees

Sagot :

AL2006
Your question is somewhat twisted up.  We would be justified in simply asking you to correct the question.  But I think I know what you're talking about, so I'll try to answer it.

A horizontal vector is one that's oriented at an angle of zero degrees, not 45 degrees.  I think what you want is the horizontal component of the vector that you're describing.

Its horizontal component is  100 cos(45)  = 100 / √2  =  70.71 units.
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