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An airplane flies due north at 100 m/s through a 30 m/s cross wind blowing from the east to the west. Determine the resultant velocity of the airplane.

Sagot :

Vf=√30²+100²
Vf=104 m/s

|Ф|=tan inverse of |100÷30|
Ф= 73 degrees

Therefore the resulting velocity of the airplaine is 104 m/s [ 73 degrees N of W]

Answer:

The resultant velocity of the airplane is 104.4 m/s.

Explanation:

It is given that,

Velocity of airplane, [tex]v_1=100\ m/s[/tex] (due north)

Velocity of wind, [tex]v_2=30\ m/s[/tex] (east to the west)

We need to find the resultant velocity of the airplane. The resultant velocity is given by :

[tex]v=\sqrt{v_1^2+v_2^2}[/tex]

[tex]v=\sqrt{(100)^2+(30)^2}[/tex]

v = 104.4 m/s

So, the resultant velocity of the airplane is 104.4 m/s. Hence, this is the required solution.