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find the absolute value of 9.8 and of -10/3.

Sagot :

The absolute value of 9.8 is 9.8. The absolute value of -10/3 is found by using your order of operations like so:
-10÷3= -3.333...
l-3.333...l = 3.333... 
By definition, the absolute value of a number is given by:
 [tex]| a | = a [/tex]
 Where,
 The number a is a real number. This means that the value of a is both negative and positive.
 The result is always greater than zero.
 Therefore, the absolute value of the given numbers is given by:
 [tex]|9.8| = 9.8[/tex]
 [tex]|-\frac{10}{3}| = \frac{10}{3} [/tex]
 Answer:
 
the absolute value of 9.8 and of -10/3 is:
 
[tex]|9.8| = 9.8[/tex]
 [tex]|-\frac{10}{3}| = \frac{10}{3} [/tex]
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