Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

If an object of 0.550 kg is lifted from the floor to a height of 3.50m, how much work is done by the lifting force, what is the kinetic energy, and what is the velocity?

Sagot :

luana
[tex]Work=\frac{Force}{distance}\\\\Force=mass*gravity\\Force=0,550*9,8=5,39N\\ distance=3,5m\\\\ Work=\frac{5,39N}{3,5m}=1,54J\\\\ Kinetic\ energy=Work=1,54J\\\\ Kinetic \ energy=\frac{1}{2}mv^2\ \ \ |*2\\ 2Kinetic \ energy=mv^2\\\ \sqrt{\frac{2Kinetic \ energy}{m}}=v\\\\ velocity=\sqrt{\frac{2*1,54}{0,55}}=\sqrt{\frac{3,08}{0,55}}=\sqrt{5,6}=2,37\frac{m}{s} [/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.