Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

How do I solve 2x+3y=7, x-y=1

Sagot :

kamil
2x+3y=7
x-y=1

2x+3y=7
x=1+y

2*(1+y)+3y=7
x=1+y

2+2y+3y=7
x=1+y

5y=5       |(:5)
x=1+y

y=1
x=2

CHECK:
2x+3y=7
x-y=1

2*2 + 3*1 = 7     

x-y = 1
2-1 = 1
2x+3y=7                                               
2(2)+3y=7                                                                                              
4+3y=7
subtract 4 from both sides                  
3y=3                                             
divide both side by 3                          
y=1
 
2x+3y=7
2x+3=7
2x+3y=7
subtract 3y from both sides
2x=7-3y
divide both side by 2
x=3.5-1.5
x=2                                     

then you do the x-y=1

x-y=1
2-1=1
1=1

in the end both answers are 1 so that means that i did it right. that means that x=2 and y=1
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.