Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
[tex]a+b=31=> \boxed{a=b-31} \\ab=234 \\\\ \\\\ b*(b-31)=234 \\\\ b^2-31b-234=0 \\ a=1 \\ b=-31 \\ c=-234 \\\\ \Delta= (-31)^2-4*1*(-234)= 961-936=25 \\\\ x_1;x_2=\frac{-(-31)+/-\sqrt{25}}{2*1} =\frac{31+/-5}{2} \\\\ x_1=\frac{31+5}{2}=\frac{36}{2}\to\boxed{18} \\\\ x_2=\frac{31-5}{2}=\frac{26}{2}\to\boxed{13} \\\\ (x-18)(x-13)=0 \\\\ 1)x-18=0 \ => \boxed{x=18} \\\\ 2)x-13=0 \ => \boxed{x=13} [/tex]
Let
x-------> the first number
y------> the second number
we know that
[tex] x+y=31 [/tex]
[tex] x=31-y [/tex]
equation [tex] 1 [/tex]
[tex] x*y=234 [/tex]
equation [tex] 2 [/tex]
substitute equation 1 in equation 2
[tex] (31-y)*y=234\\ 31y-y^{2} =234\\ -y^{2} +31y-234=0 [/tex]
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
[tex] 13 and 18 [/tex]

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.