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Write the equation of the line that is PARALLEL to the line y=-3x+12 and passes through the point (-1,6)

Sagot :

a386
This problem can be solved using the point-slope formula:
[tex]y-y_{1}=m(x-x_{1})[/tex]
Where m is the slope
x₁ is the x value provided and 
y₁ is the y value provided.

Since this line is parallel, we know it will have the same slope as the original line, which is -3.  The x₁ value is -1, and the y₁ value is 6.  Plug these numbers into the equation and solve:

[tex]y-y_{1}=m(x-x_{1})\\ y-6=-3(x+1)\\ y-6=-3x-3\\ \\y=-3x+3[/tex]
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