bellairssarah
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

How do I solve this?

3x-y=2 and 6x+3y=14 as a system of linear equations

Sagot :

Boobear1426
Problem:Solve 3x−y=2 and 6x+3y=14
Steps:I will try to solve your system of equations.3x−y=2;6x+3y=14Step:
Solve 3x−y=2 for y:3x−y+−3x=2+−3x(
Add -3x to both sides)−y=−3x+2−y−1=−3x+2−1(Divide both sides by -1)y=3x−2
Step: Substitute (3x−2) for y in 6x+3y=14:6x+3y=146x+3(3x−2)=1415x−6=14(Simplify both sides of the equation)15x−6+6=14+6(Add 6 to both sides)15x=2015x15=2015(Divide both sides by 15)x=43
Step: Substitute (43) for x in y=3x−2:y=3x−2y=3(43)−2y=2
(Simplify both sides of the equation)
Answer:y=2 and x=43
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.