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what is q+3≥9 or 9q+5<14

Sagot :

[tex]q+3\geq9 \vee 9q+5<14\\ q\geq 6 \vee 9q<9\\ q\geq 6 \vee q<1\\ q\in(-\infty,1) \cup \langle6,\infty)[/tex]
luana
[tex]First\ calculate\ inequalities\\\\ q+3 \geq 9\ \ \ |subtract\ 3\\ q \geq 6\\\\ or\\\\9q+5<14\ \ \ | subtract \ 5\\ 9q <9\ \ \ |divide\ by\ 9\\q<1\\\\Now\ find\ sum\ of\ those\ results\\\\ q \geq 6\ \ or \ \ q<1\\\\ Sum\ is\ :\\ q\in(-\infty,1) \cup [6,+\infty) [/tex]