Answered

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Please help. (1/x)<2. It says to concider 2 cases. I already got x>(1/2). How do I find another case.

Sagot :

konrad509
[tex]\frac{1}{x}<2|\cdot x^2\\ x<2x^2\\ 2x^2-x>0\\ x(2x-1)>0\\ x\in(-\infty,0)\cup(\frac{1}{2},\infty) [/tex]
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