malisa2571
Answered

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Four consecutive multiples of 10 have a sum of 300. What is the least of these numbers?
F.20
G.30
H.40
J.50
K.60

Sagot :

60 + 70 + 80 + 90  = 300

K. 60

xXxGirxXx
20 + 30 + 40 + 50 = 140 -No

30 + 40 + 50 + 60 = 180 -No

40 + 50 + 60 + 70 = 220 -No

50 + 60 + 70 + 80 = 260 -No

60 + 70 + 80 + 90 = 300 -Yes

Your final answer:
K. 60


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