Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
[tex] \frac{v-9}{10v} +6=11[/tex]
Subtracting 6 on both sides, we get,
[tex] \frac{v-9}{10v} =11-6[/tex]
[tex] \frac{v-9}{10v} =5[/tex]
Multiplying by 10v on both sides , we get,
[tex] \frac{v-9}{10v}*10v =5 *10v[/tex]
[tex]v-9=50v[/tex]
[tex]-9 = 50v -v[/tex]
[tex]-9=49v[/tex]
[tex] \frac{-9}{49} =v[/tex]
[tex]v=- \frac{9}{49} [/tex]
Subtracting 6 on both sides, we get,
[tex] \frac{v-9}{10v} =11-6[/tex]
[tex] \frac{v-9}{10v} =5[/tex]
Multiplying by 10v on both sides , we get,
[tex] \frac{v-9}{10v}*10v =5 *10v[/tex]
[tex]v-9=50v[/tex]
[tex]-9 = 50v -v[/tex]
[tex]-9=49v[/tex]
[tex] \frac{-9}{49} =v[/tex]
[tex]v=- \frac{9}{49} [/tex]
[tex]\frac{v-9}{10v+6}=11 \\\\ 11(10v+6)=v-9 \\\\ 110v+66=v-9 \\\\ 110v-v=-9-66 \\\\ 109v= -75 \\\\ \boxed{v=-\frac{75}{109}}[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.