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If ice has a density of.92g/cm, what is the volume of 1.8 kilograms of ice?

Sagot :

rabinshrestha41
Given:
Density = .92 g / cm³
Volume = 1.8 kg
            = (1.8 * 1000) grams
            = 1800 grams
Now,
[tex]Density (d) = \frac{Mass (m)}{volume(v)} [/tex]

[tex]volume (v)= \frac{mass(m)}{density(d)} [/tex]

[tex]volume (v)= \frac{1800}{.92} [/tex]

[tex]volume (v)= 1956.521739[/tex]

[tex]volume (v)= 1956.5~ cm^{3} [/tex]

So, the volume of 1.8 kg of ice is 1956.5 cm³

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