Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

What is 2x (to the second power)y (to the fourth power ) times 4x (squared) y (to the fourth power) times 3x over 3x (negative third power) y(squared)

Sagot :

mariamikayla
[tex]2x^2y^4*4x^2y^4*\frac{3xy^2}{3x^{-3}}= 8x^4y^8* \frac{3xy^2}{1}*\frac{3x^3}{1}= \\\\ =8x^4y^8*9x^4y^2= \\\\ =\boxed{72x^8y^{10}}[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.