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Sagot :
Given:
Time taken = 10,000 years
Now,
converting 10,000 years to seconds,
We have,
1 year = 365 days
= (365 * 24) hours
= (365 * 24 * 60) minutes
= (365 * 24 * 60 * 60) seconds
= 31536000 seconds
So,
Time taken = 10,000 years = (10000 * 31536000 seconds)
= [tex]3.1536 * 10^{11} seconds[/tex]
Also, according to the question,
speed = [tex]3.0* 10^{8} m[/tex]
We know,
speed = distance / time taken
speed * time taken = distance
[tex](3.0* 10^{8}) *3.1536 * 10^{11} = distance[/tex]
[tex]9.4608* 10^{19} = distance[/tex]
So, the distance across the milky way is [tex]9.4608* 10^{19}[/tex] meters.
Time taken = 10,000 years
Now,
converting 10,000 years to seconds,
We have,
1 year = 365 days
= (365 * 24) hours
= (365 * 24 * 60) minutes
= (365 * 24 * 60 * 60) seconds
= 31536000 seconds
So,
Time taken = 10,000 years = (10000 * 31536000 seconds)
= [tex]3.1536 * 10^{11} seconds[/tex]
Also, according to the question,
speed = [tex]3.0* 10^{8} m[/tex]
We know,
speed = distance / time taken
speed * time taken = distance
[tex](3.0* 10^{8}) *3.1536 * 10^{11} = distance[/tex]
[tex]9.4608* 10^{19} = distance[/tex]
So, the distance across the milky way is [tex]9.4608* 10^{19}[/tex] meters.
In standard form and units of my choosing, the distance is 10,000 light-years.
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