Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Ask your questions and receive precise answers from experienced professionals across different disciplines. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

In reaching her destination, a backpacker walks with an average velocity of 1.22 m/s, due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.53 m/s, due west, turns around, and hikes with an average velocity of 0.445 m/s, due east. How far east did she walk?

Can someone please help me please? I really really need help on this please!!!!

Sagot :

Wow! 2.95m/s is a mighty fast pace for a backpacker. Must have one of those Star Wars anti-gravity packs. Also, I would be curious as to why she passed her destination and then walked back. 
Anyway, it goes like this: 
Say the time walking east is 't', and the total time is 'T'. 
Then 5340 m + .511 t = 1.43 T 
(This assumes that velocity is positive in both directions) 
Two unknowns in one equation. But you also know that the time spent walking west is 
5340m/ 2.95m/s = 1810 sec. 
and the total time T = 1810 +t 
Substitute this into the first equation, and you can solve for t = 3092 sec. 
Then T = 4902 sec. and distance walked east is .511t = 1580m.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.