Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
[tex] \frac{1}{n-8} -1= \frac{7}{n-8} [/tex]
[tex] \frac{1-(n-8)}{n-8}= \frac{7}{n-8} [/tex]
Multiplying by (n-8) on both sides, we get,
[tex] \frac{1-(n-8)}{n-8}*({n-8})= \frac{7}{n-8} *({n-8})[/tex]
[tex]1-(n-8) = 7[/tex]
[tex]1-n+8 = 7[/tex]
[tex]-n = 7-1-8[/tex]
[tex]-n = -2[/tex]
dividing both sides by -1, we get,
[tex]n =2[/tex]
[tex] \frac{1-(n-8)}{n-8}= \frac{7}{n-8} [/tex]
Multiplying by (n-8) on both sides, we get,
[tex] \frac{1-(n-8)}{n-8}*({n-8})= \frac{7}{n-8} *({n-8})[/tex]
[tex]1-(n-8) = 7[/tex]
[tex]1-n+8 = 7[/tex]
[tex]-n = 7-1-8[/tex]
[tex]-n = -2[/tex]
dividing both sides by -1, we get,
[tex]n =2[/tex]
[tex]\frac{1}{n-8}-1=\frac{7}{n-8};\ D:n\neq8\\\\\frac{1}{n-8}-\frac{n-8}{n-8}=\frac{7}{n-8}\\\\\frac{1-(n-8)}{n-8}=\frac{7}{n-8}\\\\\frac{1-n+8}{n-8}=\frac{7}{n-8}\\\\\frac{9-n}{n-8}=\frac{7}{n-8}\iff9-n=7\ \ \ \ \ \ |subtract\ 9\ from\ both\ sides\\\\-n=-2\\\\\boxed{n=2\in D}[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.