gwendolyn555
Answered

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If 21^(2x)=9 then what is the value of 21^(-x)? Answer and solution please ;)

Sagot :

konrad509
[tex]21^{2x}=9\\ (21^x)^2=9\\ 21^x=3\\ (21^x)^{-1}=3^{-1}\\ 21^{-x}=\frac{1}{3} [/tex]
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