Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

what is the kenetic energy of 1-kilogram ball as thrown into the air with an initial velocity of 30 m/sec?

Sagot :

This problem is one tht directly involve gravity, kinetic energy is 1/2 massXvelocity^2, so .5*1*30^2=450joules, the unit for energy. 

The potential energy of it is mass times height times acceleration to gravity, 9.81. This is trickier as you have to calculate height first. 

To do this, you use the formula velocity final squared= velocity initial squared + 2*a*x, a=-9.81, final velocity = 0, initial=30, so 0=900-2*9.81x, 900/19.62=45.87ft. 

Height=45.87ft, PE=m*a*h, PE=1*9.81*45.87, so Potential energy is 450 joules. This makes sense since with energy conserved, when KE=0, PE must equal the previous KE, and when PE=0, KE must equal that constant 

Formulas: 

KE=1/2*m*v^2 
PE=m*g*h 
Vf^2=Vi^2+2ax 
Vf=0, Vi=30, g=9.81, m=1
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.