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The perimeter of a triangle ABC is 54. The triangle has side lengths AB=3x,BC=4x,and AC=5x. Find the length of each side.

Sagot :

W0lf93
The perimeter is all the sides added together so: 3x + 4x + 5x = 54. 12x = 54. x = 54/12. x = 4.5. Then AB = 3 x 4.5. BC = 4 x 4.5. AC = 5 x 4.5. AB = 13.5, BC = 18, AC = 22.5.