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given: quadrilateral ABCD with ∠A= ∠C and BD the bisector ∠ABC 
prove: DB bisects
 ∠ADC


Sagot :

ΔABD ≡ ΔCBD ( L.U.U) because (BD)≡(BD), ∠A≡ ∠C , <ABD≡<CBD => <ADB ≡ <CDB =>DB bisects ∠ADC;
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