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Sagot :
Answer-
The width of the pieces of construction paper is [tex]6\dfrac{3}{4}\ \text{inch}[/tex]
Solution-
James has a piece of construction paper with an area [tex]65\dfrac{1}{4}=\dfrac{261}{4}[/tex] inch²
Length of the paper is [tex]9\dfrac{2}{3}=\dfrac{29}{3}[/tex] inch
We know that,
[tex]\text{Area}=\text{Length}\times \text{Width}[/tex]
Putting the values,
[tex]\Rightarrow \dfrac{261}{4}=\dfrac{29}{3}\times \text{Width}[/tex]
[tex]\Rightarrow \text{Width}=\dfrac{261}{4}\times \dfrac{3}{29}[/tex]
[tex]\Rightarrow \text{Width}=\dfrac{9\times 3}{4}[/tex]
[tex]\Rightarrow \text{Width}=\dfrac{27}{4}[/tex]
[tex]\Rightarrow \text{Width}=6\dfrac{3}{4}\ \text{inch}[/tex]
Therefore, the width of the pieces of construction paper is [tex]6\dfrac{3}{4}\ \text{inch}[/tex]
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