Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Write a system of equations with a solution (4,–3)

Sagot :

taskmasters
1.       So we have the system of equation. (4, -3)
let’s create another system of equation.
Let a = 4
and Let b = -3
First equation
=> Let’s pick any numbers to be used. Let’s have number 5
=> 5a + 5b
=> 5 (4) + 5 (-3)
=> 20 + (-15)
negative and positive is equals to negative
=> 20 – 15
=> 5 (this the first value of our equation, let this be the value of X)

Second
=> Pick another number, Let’s have 6
=> 6a + 6b
=> 6 (4) + 6 (-3)
=> 24 + (-18)
=> 24 – 18
=> 6 (this is the value of our second equation, let this value be Y)

Now, we have (A, B) = (4, -3) and (X, Y) = (5,6)



24demarsc

Answer:

A linear equation can be written in several forms. "Standard Form" is #ax+by=c# where #a#, #b# and #c# are constants (numbers).

We want to make two equations that

(i) have this form,

(ii) do not have all the same solutions (the equations are not equivalent), and

(iii) #(4, -3)# is a solution to both.

#ax+by=c#. We want #a#, #b# and #c# so that

#a(4)+b(-3)=c# (This will make (i) and (iii) true.)

Step-by-step explanation:

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.