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How many atoms are in 0.750 moles of zinc?

Sagot :

(doesn't really matter that it's zinc :) )
It is [tex]0.75*N_A[/tex], where [tex]N_A=6.023*10^{23}[/tex] (in some books 6.022).
4.52 X 10²³ atoms

Use Avogadro's number to multiply 0.750 moles times 6.022 X 10²³ atoms.

Then divide by 1 atom to get the answer. hope that helped
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