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Divide 80 in a ratio of 3:2

Sagot :

Answer:

Let the number be x

Ratio states that as the comparison of sizes of two quantities of the same unit.

Given : Ratio 3:2

The first number be 3x and

the second number be 2x.

then,

As per the condition:

[tex]3x+2x=80[/tex]

Combine like terms;

5x = 80

Divide both sides by 5 , to solve for x;

[tex]\frac{5x}{5}= \frac{80}{5}[/tex]

Simplify:

x=16

Then, the numbers are:

[tex]3x =3 \times 16 = 48[/tex] and

[tex]2x =2 \times 16 = 32[/tex].

Therefore, the number 80 is divided in the ratio of 3:2 is, 48 and 32.



Two numbers with a ratio of 3: 2 and the number 80 are: 48 and 32

Further explanation

Comparison is an effort to compare two or more objects in terms of shape or size, or number

Proportional Comparisons  are comparisons of two or more numbers where one number increases, the other numbers also increase

Can be formulated

[tex]\frac{x1}{y1}=\frac{x2}{y2}[/tex]

so that if:

x = 2

then

[tex]y=\frac{y}{x}\times\:2[/tex]

While the reversal value comparison is the comparison of two or more numbers where one number increases, the other number decreases in value

can be formulated

[tex]\frac{x1}{y2}=\frac{x2}{y1}[/tex]

so that if:

x = 2

then

[tex]y=\frac{x}{y}\times\:2[/tex]

The total number of two numbers = 80 with a comparison of the two numbers = 3: 2

then the total comparison of the two numbers = 3 + 2 = 5

  • 1. first number

3/5 x 80 = 48

  • 2. second number

2/5 x 80 = 32

So we get both numbers = 48 and 32

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Keywords: division, comparison, ratio

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