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Roger pushes a box on a 30° incline. If he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

Sagot :

Work done= Force * Distance

1) We need to workout the components of the box
:. 30degress. so 1 component going perpendicular (Up) is 60sin30
2nd component going parallel (straight) is 60cos30

2) We need to use 60cos30 because roger is pusing the box parallel

3) 60cos30=51.965...... N      This is the FORCE

4) workdone = 51.965... * 10 = 519.615..... Joules

5) Answer is 520 Joules (to 3 significant figures)

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