Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

The length of a rectangular deck is 4 times its width. If the deck's perimeter is 30 feet, what is the deck's area?

Sagot :

luana
[tex]Perimeter\ of\ rectangular\ deck=2width+2lenght\\\\ length=4width\\\\ 30=2width+2(4width)\\\\ 30=2width+8width\\\\ 30=10width\ \ \ \ |divide\ by\ 10\\\\ width=3feet\\\\ Area=width*length\\\\ Area=3*4=\boxed{12feet^2}[/tex]
gamegirl3596
36 square feet because the width would be a and so since the length is 4 times that you can say that the two sides added together would be 5a
30 feet is the parameter which would include all 4 sides but we are only looking for 2 sides so you can divide that by 2 so 
5a=15       so divide 15 by 5 and you get 3 so a=3
4a=4*3= 12=length
a=3=width
length*width=area
12*3= 36 square feet
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.