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Sagot :
You need to know the energy frequency relationship for photons, which is thanks to Max Planck:
Photon Energy = Planck constant x Frequency
Rarranged:
Photon Energy / Planck Constant = Frequency
Planck Constant = 6.63x10^-34
2.93x10^-25 / 6.63x10^-34 = Frequency
Photon Energy = Planck constant x Frequency
Rarranged:
Photon Energy / Planck Constant = Frequency
Planck Constant = 6.63x10^-34
2.93x10^-25 / 6.63x10^-34 = Frequency
Answer: The radiation has a frequency of [tex]4.43\times 10^{9}Hz[/tex] and is a type of radio wave.
Explanation:
The equation given by Planck's follows:
[tex]E=h\nu[/tex]
where,
E = energy of the light = [tex]2.93\times 10^{-25}J[/tex]
h = Planck's constant = [tex]6.62\times 10^{-34}Js[/tex]
[tex]\nu[/tex] = frequency of light = ?
Putting values in above equation, we get:
[tex]2.93\times 10^{-25}J=6.62\times 10^{-34}Js\times \nu\\\\\nu=\frac{2.93\times 10^{-25}J}{6.62\times 10^{-34Js}}=4.43\times 10^{9}Hz[/tex]
The relation between frequency and wavelength is given as:
[tex]\nu=\frac{c}{\lambda}[/tex]
where,
c = the speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\nu[/tex] = frequency of radiation = [tex]4.43\times 10^{8}s^{-1}[/tex]
[tex]\lambda[/tex] = wavelength of the radiation = ?
Putting values in above equation, we get:
[tex]4.43\times 10^{8}s^{-1}=\frac{3\times 10^8m/s}{\lambda}\\\\\lambda=\frac{3\times 10^8m/s}{4.43\times 10^8}s^{-1}}=0.677m[/tex]
The radiation having wavelength 0.677 m belongs to radio waves.
Hence, the radiation has a frequency of [tex]4.43\times 10^{9}Hz[/tex] and is a type of radio wave.
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