Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Graph the line using intercepts: 4x-3y=12

Sagot :

hwangj1999
First you have to find the intercepts!

To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).

Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).

So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.

hope that helped~
View image hwangj1999
deathstrike001
Graph the intercepts by assigning the balue to y or x then after u assign u will graph it. Since it is a linear equation it might be easier so it may be a  line not a parabola

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.