At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
a)
2revs in 0.08s
so in 1s thats 25revs
therefore thats 50π radians in one second
b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
and v=rω where r is in meters;
v=0.3x157.079
v=47.123ms^-1
c)
f=1/T
f=1/period for one rotation
1 rotation = 0.08/2 = 0.04
f=1/0.04
f=25Hz
2revs in 0.08s
so in 1s thats 25revs
therefore thats 50π radians in one second
b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
and v=rω where r is in meters;
v=0.3x157.079
v=47.123ms^-1
c)
f=1/T
f=1/period for one rotation
1 rotation = 0.08/2 = 0.04
f=1/0.04
f=25Hz
(a) The angle of the rotation of the wheel in 1.0 seconds is 157.1 radians.
(b) The linear speed of a point on the wheel's rim is 47.13 m/s.
(c) The wheel's frequency of rotation is 1500 rpm.
The given parameters;
- radius of the wheel, r = 30 cm = 0.3 m
- angular speed of the wheel, ω = 2 rev for 0.08 s
The angle of the rotation in 1.0 seconds is calculated as;
[tex]\theta = \omega t\\\\\theta = (\frac{2 \ rev}{0.08 \ s} \times \frac{2\pi \ rad }{1 \ rev} ) \times 1\\\\\theta = 157.1 \ rad[/tex]
The linear speed of the wheel is calculated as follows;
[tex]v = \omega r\\\\v = (\frac{2 \ rev}{0.08 \ s} \times \frac{2\pi \ rad}{1 \ rev} ) \times 0.3\\\\v = 47.13 \ m/s[/tex]
The wheel's frequency of rotation is calculated as follows;
[tex]N = \frac{2 \ rev}{0.08 \ s} \times \frac{60 \ s}{1 \min} \\\\N = 1500 \ RPM[/tex]
Learn more here:https://brainly.com/question/14453709
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.