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At open skate night, admission is $3.75 with a membership card and $5.00 without a membership card. Skate rentals are $3.00.
The Moores And Cotters were at Open Slate night. The moores paid $6.00 more for skate rentals than the Cotters did. Together, the two families paid $30 for skate. How many pairs of skates did the Moores rent?

Sagot :

anniedavies96
price paid:
moores = cotters + 6

moores + cotters + 6 = 30
therefore:
moores + cotters = 24
[substitute moores = cotters + 6 into moores + cotters = 24]
cotters + 6 + cotters = 24
2 cotters = 18
cotters = 9

[substitute cotters = 9 into moores = cotters + 6]
moores = 9 + 6 = 15

you haven't said of the families have membership, but on skate rentals alone:

15 / 3 = 5 pairs of skates

Answer:

The Moore spent 3(18)=$54.

The Cotters spent 3(12)=$36.

Step-by-step explanation:

The problem doesn't specifies which family has membership card, and which one doesn't.

According to the problem, The Moore's paid $6.00 more than the Cotter's. Both families paid $30. So, with this relations we can solve the problem.

The difference between families is represented by:

[tex]M=C+6[/tex]

And the total amount of money is:

[tex]M+C=30[/tex]

Replacing the first equation in the second one:

[tex]C+6+C=30[/tex]

[tex]2C=30-6\\C=\frac{24}{2}=12[/tex]

Replacing this value in the second equation, we have:

[tex]M+12=30[/tex]

[tex]M=30-12=18[/tex]

According to these results, the Moore's rented 18 pair of skates, and the Cotter's 12 pairs.

If Skate rental are $3.00, then:

The Moore spent 3(18)=$54.

The Cotters spent 3(12)=$36.

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