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Sagot :
7/8 gallons in 1/2 hour
Looking for gallons per hour, or [tex]\frac{gallons}{hour}[/tex].
So, this is basically a division problem of 7/8 divided by 1/2. Dividing by a fraction is the same as multiplying by that fraction's reciprocal.
[tex]\frac{7/8}{1/2}\frac{gallons}{hour}[/tex]
[tex]\frac{\frac{7}{8}}{\frac{1}{2}} = \frac{7}{8} * \frac{2}{1} = \frac {7}{8} * 2 = \frac{14}{8}[/tex]
Now we simplify by a factor of 2:
[tex]\frac{14}{8} = \frac{7}{4}[/tex]
And here we are! There are 7/4 gallons leaking per hour. This is the same as 1.75 gallons per hour. Hope this helps! :)
Looking for gallons per hour, or [tex]\frac{gallons}{hour}[/tex].
So, this is basically a division problem of 7/8 divided by 1/2. Dividing by a fraction is the same as multiplying by that fraction's reciprocal.
[tex]\frac{7/8}{1/2}\frac{gallons}{hour}[/tex]
[tex]\frac{\frac{7}{8}}{\frac{1}{2}} = \frac{7}{8} * \frac{2}{1} = \frac {7}{8} * 2 = \frac{14}{8}[/tex]
Now we simplify by a factor of 2:
[tex]\frac{14}{8} = \frac{7}{4}[/tex]
And here we are! There are 7/4 gallons leaking per hour. This is the same as 1.75 gallons per hour. Hope this helps! :)
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