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Solve for x. 2cosxsinx=0

Sagot :

conungi
the first step would be to divde both sides by 2. then you would have to find where cos(x) times sin(x) would equal 0. to do that either cos(x) OR sin(x) would heve to be zero becasue any number times zero equals zero. n is an inteager (whole Number) cos(x) equals pi/2 plus pi times n.[tex]2cos(x)sin(x)=0 \\ cos(x)sin(x)=0 \\ cos(x)=0 \\( \pi /2) + \pi n\\ sin(x)=0 \\ 0 + \pi n[/tex]
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